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Math · Updated 2026

Combinations & Permutations Calculator

Instantly calculate the number of combinations C(n,r) and permutations P(n,r) — useful for lottery, probability and statistics.

Enter n and r

Combinations C(n,r): order does NOT matter. Permutations P(n,r): order matters.

=Combinations
13,983,816
n, r49, 6
Combinations — C(n,r)13,983,816
Permutations — P(n,r)10,068,347,520

Standard mathematical formulas. Instant in-browser calculation, no account. Exact results, big numbers computed precisely.

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iHow it is calculated

In combinations the order does not matter; in permutations it does. Both are computed from factorials:

C(n,r) = n! ÷ (r!(n−r)!) · P(n,r) = n! ÷ (n−r)!

In a 6/49 lottery: C(49, 6) = 13,983,816 combinations. To choose 2 of 5: C(5,2) = 10, P(5,2) = 20.

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?Frequently asked questions

What is the difference between combinations and permutations?

In combinations the order does NOT matter (a group of people); in permutations the order matters (a ranking or a password).

How do I calculate combinations C(n, r)?

C(n, r) = n! ÷ (r! × (n−r)!). For example, C(5, 2) = 10 ways to choose 2 out of 5.

How do I calculate permutations P(n, r)?

P(n, r) = n! ÷ (n−r)!. For example, P(5, 2) = 20 ways to arrange 2 of 5 (order matters).

How many combinations are there in a 6/49 lottery?

C(49, 6) = 13,983,816 possible combinations. The chance of the jackpot is 1 in almost 14 million.

When do I use combinations vs permutations?

Combinations when you select without regard to order (a poker hand); permutations when order matters (podium places).

In how many ways do I choose 2 items from 5?

C(5, 2) = 10 if order does not matter, or P(5, 2) = 20 if order matters.

What is an arrangement?

An arrangement of r items from n is a partial permutation — you pick r items and put them in order. It is written P(n, r).

What are they used for in real life?

Lotteries, passwords and codes, forming teams, menus, probability and statistical analysis.

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